Old Posted: 3/4/2015 1:34:05 PM   #1
 
Join Date: 10/9/2003 6:36:15 PM

Default  Page 110, Figure 3.50

On both glucose molecules to the left of the reaction arrow, the top right carbon (directly sleft of the oxygen in the ring) should have an extra carbon between the ring carbon and the hydroxyl. These extra carbons should also appear on the two rings of the maltose to the right of the reaction arrow – the top right carbon of each ring should have a bond to –CH2OH. See new visual: http://examkrackers.com/pdf/CHEMISTRY-LECTURE-3-p-110-Figure3-50.pdf
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